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Faraday's Law of Electrolysis Calculator

Mass of metal deposited or gas evolved from current and time — or the time and charge needed for a target mass — for any ion with its molar mass and charge, with efficiency and gas volume at STP.

Solve for
Species
Molar mass (custom)
Electrons per formula unit (custom)
Current
Time (mass mode)
Target mass (time mode)
Current efficiency
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How it works

m = (I·t ÷ F) × (M ÷ z) × efficiency, F = 96,485 C/mol; t = m·z·F ÷ (I·M·η)

Faraday found that the mass produced at an electrode is proportional to the charge passed and to the molar mass divided by the number of electrons each ion needs — one faraday (96,485 C) deposits one equivalent. That makes electroplating and refining exactly predictable: 1 A for 1 hour deposits 1.19 g of copper or 4.02 g of silver. Real cells run below 100% current efficiency because side reactions (hydrogen evolution, for instance) consume some of the charge.

Worked example

2.5 A for 60 minutes = 9,000 C = 0.0933 mol e⁻; copper (z = 2) gives 0.0466 mol = 2.96 g at 100% efficiency.

Frequently asked questions

How many electrons for water electrolysis?

2 per H₂ and 4 per O₂ — so hydrogen is produced at twice the molar rate of oxygen.

Why is aluminium so energy-hungry?

Three electrons per atom of a light metal: 1 kg needs 3 × 96,485 × 37 mol ≈ 10.7 million coulombs, at 4 V about 12 kWh.

Related calculators

For study and planning — check units and conditions against your data source before using a result in the lab.