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Heat Conduction Calculator

Find the steady-state heat flow through a wall or slab using Fourier's law of conduction.

Thermal conductivity k
Cross-sectional area
Temperature difference
Thickness
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How it works

Q = k · A · ΔT ÷ d · (d = thickness)

Fourier's law says heat flows through a material in proportion to its conductivity k, its face area A, and the temperature difference across it, and inversely with its thickness d. A good insulator has a small k, so a thin layer of fibreglass slows heat far more than a thick slab of brick. The result is the steady-state power in watts crossing the material.

Worked example

A 10 m² fibreglass panel (k = 0.04 W/m·K), 0.1 m thick, with 20 K across it, conducts Q = 0.04 × 10 × 20 ÷ 0.1 = 80 W.

Sources: Thermal conduction — Wikipedia

Frequently asked questions

What is thermal conductivity?

It is a material property, k, in W/m·K, measuring how readily it conducts heat. Metals like copper (~400) conduct extremely well; insulators like fibreglass (~0.04) conduct poorly, which is exactly what makes them good insulation.

How does thickness affect heat loss?

Heat flow is inversely proportional to thickness: doubling the insulation thickness halves the conductive heat loss, all else equal.

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This calculator is for educational purposes. Double-check important results before acting on them.