Common Ion Effect Calculator
See how much a 1:1 salt’s solubility drops when a common ion is already present, solved from its Ksp and the common-ion concentration.
How it works
For AB with a common ion at C: s² + C·s − Ksp = 0 → s = ( −C + √(C² + 4·Ksp) ) / 2
The common ion effect is the drop in a salt’s solubility when the solution already contains one of its ions. By Le Chatelier’s principle the added ion pushes the dissolution equilibrium backward, so less solid dissolves. For a 1:1 salt the exact solubility solves the quadratic Ksp = s(s + C); when C is much larger than s this reduces to the familiar s ≈ Ksp / C.
Worked example
AgCl (Ksp = 1.8 × 10⁻¹⁰) in pure water dissolves to √Ksp = 1.34 × 10⁻⁵ M. In 0.10 M NaCl the chloride is a common ion: s = (−0.10 + √(0.01 + 7.2 × 10⁻¹⁰)) / 2 ≈ 1.8 × 10⁻⁹ M — about 7,400 times less soluble.
Sources: Common-ion effect — Wikipedia
Frequently asked questions
What is the common ion effect?
It is the reduction in solubility of an ionic solid caused by having one of its own ions already dissolved from another source. The extra ion shifts the solubility equilibrium toward the solid.
Why solve a quadratic rather than use Ksp / C?
Ksp / C is an approximation valid only when the common-ion concentration greatly exceeds the salt’s own solubility. The quadratic Ksp = s(s + C) stays exact even when they are comparable.
Does this apply to non-1:1 salts?
The idea applies to all sparingly soluble salts, but the equation changes with stoichiometry. This calculator solves the 1:1 (AB) case exactly; other ratios need their own Ksp expression.
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This calculator is for educational purposes. Double-check important results before acting on them.