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Raffle Odds & Expected Value Calculator

Work out your chance of winning a raffle or prize draw from tickets bought, tickets sold and the number of prizes — at least one win, exactly 1, 2 or more wins, odds against, expected value, tickets needed for a 50% or 90% chance, several raffles at once, and an organiser view for proceeds and break-even sales.

Who are you?
Tickets you hold
Total tickets in the draw
Number of prizes (each drawn from the remaining tickets)
Price per ticket
Average prize value
Can one ticket win more than once?
Number of similar raffles you enter
Other costs (printing, licence, fees)
Fundraising goal (net)
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How it works

P(no win) = Π (T − m − i) ÷ (T − i) for i = 0 … P−1 (without replacement) or (1 − m/T)^P (with replacement) · P(exactly k) = C(m, k) × C(T − m, P − k) ÷ C(T, P) · P(≥ 1 win) = 1 − P(no win) · expected wins = m × P ÷ T · EV = expected wins × prize − tickets × price · net proceeds = T × price − prizes − costs

In a raffle every ticket has the same chance, so the probability that a particular prize goes to one of yours is simply your share of the tickets — and with several prizes the expected number of wins is that share times the prize count. The chance of winning at least once is easiest to reach through its opposite, the chance every prize misses you, which is a product of shrinking fractions as winning tickets leave the drum. The full spread — exactly 0, 1, 2 or more wins — follows the hypergeometric distribution (or the binomial if winning tickets go back in). Expected value compares what you paid with what the average ticket returns and, since charity raffles keep most of the pot, it is nearly always negative. Under More options you can enter how many similar raffles you play to see the combined chance. Switch to Organiser to see ticket revenue, net proceeds after prizes and costs, break-even sales and the tickets needed to reach a fundraising goal.

Worked example

Five tickets out of 500 with three prizes: the chance of at least one win is 1 − (495/500 × 494/499 × 493/498) ≈ 2.98%, about 1 in 34, and the expected number of wins is 0.03. At $2 a ticket you paid $10 for an expected $3 of prize value; 103 tickets would be needed for a 50% chance. As the organiser, selling all 500 tickets raises $1,000; after $300 of prizes you keep $700, and you break even at 150 tickets.

Frequently asked questions

Do more tickets in the drum change my odds if I buy the same number?

Yes — your chance is your share of the total. Five tickets in 500 is 1%, five in 5,000 is 0.1% per prize. Ask how many tickets were sold before deciding whether the odds are worth it.

Is buying half the tickets a 50% chance?

For a single prize, exactly. With several prizes, holding half the tickets gives well over a 50% chance of at least one win (87.5% for three prizes) because you have several shots.

Does it matter whether winning tickets go back in the drum?

A little. When winners are removed, the remaining tickets have slightly better odds for the next prize, so your chance of at least one win is a bit higher than with replacement. With 10 of 500 tickets and 10 prizes it is 18.4% without replacement versus 18.3% with.

What are my odds over several raffles?

Enter the number of raffles under More options. If each has the same odds, the chance of winning at least once is 1 − (chance of no win)^N: a 3% chance per raffle becomes about 26% over 10 raffles.

How many tickets does an organiser need to sell?

Choose Organiser. Break-even sales are (prize cost + other costs) ÷ ticket price, and the tickets for a goal add the goal to the costs first. With $300 of prizes, $50 of printing and $2 tickets you break even at 175 tickets.

Related calculators

Exact probabilities under the standard rules and fair dice; house rules, variants and the human choices in a real game change the numbers.