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Van't Hoff Equation Calculator

How an equilibrium constant changes with temperature — K at a new temperature from ΔH°, or ΔH° from two K values — with ΔS° and the direction Le Chatelier predicts.

Solve for
K₁
T₁
T₂
ΔH° (K₂ mode)
K₂ (ΔH° mode)
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How it works

ln(K₂/K₁) = −(ΔH°/R)·(1/T₂ − 1/T₁); ln K = −ΔH°/(RT) + ΔS°/R (a plot of ln K vs 1/T has slope −ΔH°/R)

Integrating d(ln K)/dT = ΔH°/RT² gives the van’t Hoff equation, which quantifies Le Chatelier: exothermic reactions have smaller K at higher temperature, endothermic ones larger. Measuring K at several temperatures and plotting ln K against 1/T yields ΔH° from the slope and ΔS° from the intercept — the standard way to get reaction thermodynamics from equilibrium data, from ammonia synthesis to protein unfolding and drug binding. It assumes ΔH° is roughly constant over the range.

Worked example

Ammonia synthesis, K = 6 × 10⁵ at 298 K, ΔH° = −92.2 kJ: at 500 K, ln(K₂/K₁) = 11,090 × (1/500 − 1/298) = −15.0, so K₂ ≈ 0.18 — a 3-million-fold drop.

Frequently asked questions

Is it the same as the Clausius–Clapeyron equation?

Same mathematics: Clausius–Clapeyron is the van’t Hoff equation applied to vaporisation, with vapour pressure playing the role of K.

What if ΔH changes with temperature?

Include ΔCp (Kirchhoff’s law) or use the integrated form over short intervals; over a few hundred kelvin the error is usually modest.

Related calculators

For study and planning — check units and conditions against your data source before using a result in the lab.